Sum of Fibonacci Numbers
The problem
Given an integer n, return the sum of the first n Fibonacci numbers, starting with 0 and 1.
The Fibonacci sequence is defined as: F(0) = 0 F(1) = 1 F(n) = F(n - 1) + F(n - 2) for n ≥ 2
You are required to return the sum F(0) + F(1) + ... + F(n).
Input: n = 3 **Output: **4 Explanation: F(0) + F(1) + F(2) + F(3) = 0 + 1 + 1 + 2 = 4
Input: n = 5 Output: 12 **Explanation: **0 + 1 + 1 + 2 + 3 + 5 = 12
**Input: **4
- 0 <= n <= 50
cpp
class Solution {
public:
long long sumFibonacci(int n) {
// Your code goes here
}
};java
class Solution {
public long sumFibonacci(int n) {
//Your code goes here
}
}python
class Solution:
def sumFibonacci(self, n: int) -> int:
# Your code goes herejavascript
class Solution {
sumFibonacci(n) {
// Your code goes here
}
}csharp
class Solution {
public long SumFibonacci(int n) {
// Your code goes here
}
}go
func sumFibonacci(n int) int64Stuck? Show a way to structure it+
- 01State the identity sum through F(n) equals F(n plus 2) minus one.
- 02Compute Fibonacci values iteratively.
- 03Use a wide enough numeric type.
- 04Subtract one from F(n plus 2).
Reference answer
Then expect these follow-ups
How would fast doubling reduce runtime to O(log n)?
Tests: complexity analysis
Can you derive a similar identity for even-indexed terms?
Tests: follow-up reasoning
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